[بسمة ألـم]

ودا حل فقره 5


#include<conio.h>
#include<math.h>
int main(void)
{
double x,y,z;
int a,b,c;
char d;
do
{
printf("Enter first num");
scanf("%lf",&x);
printf("Enter second num");
scanf("%lf",&y);
printf("Enter the operation +,-,*,/\n");
scanf("%c",&d);
switch(d)
{
case '+':z=x+y;
printf("%f+%f=%f",x,y,z);
break;
case '-':z=x-y;
printf("%f-%f=%f",x,y,z);
break;
case '*':z=x*y;
printf("%f*%f=%f",x,y,z);
break;
case '/':
if(y==0){
printf("cann't calculate");}
else
{z=x/y;
printf("%f/%f=%f",x,y,z);}
break;
case '%': z= (a)%(b);


printf("%d % %d= %f",a,b,z);
break;
default:printf("cann't calculate");
break;
}
printf("\nto calculate press 1\n");
scanf("%d",&c);
}while(c==1);

getch();
}


ودا رقم 6


#include<stdio.h>
#include<conio.h>
#include<math.h>
int main(void)
{
double x,y,z;
int a,b,c;
char d;
while(c==1);
printf("Enter first num");
scanf("%lf",&x);
printf("Enter second num");
scanf("%lf",&y);
printf("Enter the operation +,-,*,/\n");
scanf("%c",&d);
switch(d)
{
case '+':z=x+y;
printf("%f+%f=%f",x,y,z);
break;
case '-':z=x-y;
printf("%f-%f=%f",x,y,z);
break;
case '*':z=x*y;
printf("%f*%f=%f",x,y,z);
break;
case '/':
if(y==0){
printf("cann't calculate");}
else
{z=x/y;
printf("%f/%f=%f",x,y,z);}
break;
case '%': z= (a)%(b);


printf("%d % %d= %f",a,b,z);
break;
default:printf("cann't calculate");
break;
}
printf("\nto calculate press 1\n");
scanf("%d",&c);


getch();
}


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