الفصل الثالث(فيزياء): المتجهات

[ALI ALZAHRANI]

المشاركة الأصلية كتبت بواسطة نوف18 الله يجزاك الجنه ويوفقك يآآآآآآآآآآآآآآآآآآآآآآآآآآرب عندي اسئله ××× 1) the x component of vector A is -25.0 m and the y component is + 40.0 m (a) what is the magnitude vector A ? The magnitude of the vector A is given by: A = (Ax^2 + Ay^2)^0.5=([-25]^2+40^2)=47.2 m (b) what is the angle between the direction of vector A and the positive direction of x ? The angle the vector A makes with x-axis is given by: Ax = AcosQ therefore the angle is Q=cos-1(Ax/A)=cos1-(-25/47.2)=121.98 ××× 3) what are (a) the x component and (b) the y component of a vector a in the xy plane if its direction is 250 counterclock wise from the positive direction of the x axis and magnitude is 7.3 m? The x-component of the vector A is given by: Ax = AcosQ=7.3 cos250=-2.5 The y-component of the vector A is given by: Ax = AsinQ=7.3 sin250=-6.85 ××× 6)a displacement vetor r in the xy plane is 15 m long and directed at angle ∂=30 in fig 3-29.determine (a) the x component and (b) the y component of the vector. The x-component of the vector r is given by: rx = r cosQ=15 cos30=13.0 The y-component of the vector r is given by: rx = r sinQ=15 sin30=7.5 ××× 13 ) two vectors are given by a= (4.0m)i - (3.0m)j = (1.0m)k b= (-1.0m)i - (1.0m)j = (4.0m)k in unit-vector notation , find (a) a+b,(b) a - b and (c) a third vector c such that a - b + c=0 a+b = 5i - 2j - 3k a+b = 3i - 4j +5k a-b+c=0 ======> c= b-a = -5i + 2j +3k ××× 17) the two vector a and b in fig 3-30 have equal magnitudes of 10.0 m and the angles are ∂1=30 and ∂2=105. find the (a) x and (b) y components of their vector sum r , (c) the magnitude of r, and (d) the angle r make with the positive direction of the x axis ax = a cosQ1=10 cos30=8.66 ay = a sinQ1=10 sin30=5.0 bx = b cosQ2=10 cos135=-7.07 by = b sinQ2 =10 sin135=7.07 rx = ax+bx=8.66-7.07=1.59 ry = ay+by=5.0+7.07=12.07 The magnitude of the vector r is r = (rx^2 + ry^2)^0.5=(1.59^2+12.07^2)=12.2 m The angle the vector r makes with x-axis is given by: rx = r cosQ therefore the angle is Q=cos-1(rx/r)=cos1-(1.59/12.2)=82.5 ×××

Please make another iteration to realise the calculation