مساعدة في برمجة cpcs202

[ZeroOne]

أتمنى مساعدتكم في حل هذا البرنامج وهي عبارة عن آلة حاسبة بسيطة .. وفي الصورة الـ output للبرنامج

[Turki 7bb]

boolean run = true ;
        while (run) {
        System.out.println("Calculator Program");
        System.out.println("=============================================");
        System.out.println("1. For additon of two numbers"+"\t"+"Press 1");
        System.out.println("2. For additon of two numbers"+"\t"+"Press 2");
        System.out.println("3. For additon of two numbers"+"\t"+"Press 3");
        System.out.println("4. For additon of two numbers"+"\t"+"Press 4");
        System.out.println("5. For additon of two numbers"+"\t"+"Press 5");
        System.out.println("6. For additon of two numbers"+"\t"+"Press 0");
        System.out.println("=============================================");
        
        Scanner i = new Scanner (System.in);
        System.out.print("Enter Your choice: ");
        int x = i.nextInt();
        if (x==1)
        System.out.println("Calculator Program - addition of two numbers");  
        
        else if (x==2)
        System.out.println("Calculator Program - addition of two numbers");   
        
        else if (x==3)
        System.out.println("Calculator Program - addition of two numbers");    
        
        else if (x==4)
         System.out.println("Calculator Program - addition of two numbers");   

        else if (x==5)
         System.out.println("Calculator Program - addition of two numbers");   
        
        else {
            
        }
        System.out.println("=============================================");
        System.out.print("Enter the first number: ");
        double n1 = i.nextInt();
        System.out.print("Enter the second number: ");
        double n2 = i.nextInt();
        
        double n3 ;
        
        if (x==1){
            n3 = n2+n1;
        System.out.println("additon of "+n1+" and "+n2+" is "+n3);  
        }
        else if (x==2){
            n3 = n2-n1;
        System.out.println("additon of "+n1+" and "+n2+" is "+n3);  
        }  
        
        else if (x==3){
            n3 = n2*n1;
        System.out.println("additon of "+n1+" and "+n2+" is "+n3);  
        }    
        
        else if (x==4){
            n3 = n2/n1;
        System.out.println("additon of "+n1+" and "+n2+" is "+n3);  
        }   

        else if (x==5){
            n3 = n2%n1;
        System.out.println("additon of "+n1+" and "+n2+" is "+n3);  
        }   
        
        else {
            
        }
        System.out.println("Do you want to continue ? ");
        System.out.println("Press 1 to continue");
        System.out.println("Press 0 to finish the program");
        System.out.println("=============================================");
        System.out.print("Enter Your choice: ");
        int y = i.nextInt();
        
        if (y==1)
            run = true ;
        else if (y==0)
            run = false ;

سويتو ع السريع واوامر سهله بدون مثود او مصفوفات ويوجد بعض الاخطاء الاملائية للطباعة للوقت ههههه :) بالتوفيق

[ZeroOne]

شكراً تركي على المساعدة والله يكتب لك الأجر

..

أتمنى أحد يساعدني في حل هذا الاسايمنت ويسرد لي شرح بسيط اذا قدر حتى أفهم لاني ما حضرت أغلب محاضرات المثيود :(