Cpcs 202 شروحات وحلول وواجبات الجافا

[الفَرس]

كيف اعرف الثابت بأكثر من قيمه ؟

[سملّق :)]

diva

في المسألة الأولى :

هذا البرنامج صحيح 100% .. ولكن عندك خطأين فقط

وهذا هو الكود حق البرامج بعد التعديل ، وتظهر الاخطاء ملونة بـ " الاحمر "

 
package baseconvert;
import java.util.Scanner;
public class BaseConvert 
{
 public static void main(String[] args) 
 {
 
  int base10Num,BNum;
  int maxNumber1 , maxNumber2 , maxNumber3,maxNumber4 ;
  int quotient1, quotient2, quotient3, quotient4;
 
  Scanner keyboard = new Scanner(System.in);
 
  System.out.println("Enter base 10 number");
  base10Num= keyboard.nextInt();
 
  System.out.println("Enter a new base");
  BNum= keyboard.nextInt();
 
  quotient1= base10Num / BNum ;
  maxNumber4= base10Num % BNum ;
 
  quotient2= quotient1 / BNum ;
  maxNumber3=quotient1 % BNum ;
 
  quotient3= quotient2 / BNum ;
  maxNumber2= quotient2 % BNum ; 
 
  quotient4= quotient3 / BNum ;
  maxNumber1= quotient3 % BNum ; 
 
  System.out.println("The value of new base equal" + maxNumber4 + maxNumber3 + maxNumber2 + maxNumber1);
 }
}

الخطأ الأول ::: انتي نسيتي كلمة ( base ) !

الخطأ الثاني ::: أمر الطباعة System.out.println("") المفروض يجي في آخر البرنامج !

ليه ؟ ... لأن البرنامج انتي أعطيتيه أمر طباعة نتيجة !! والبرنامج اساساً ما حل جميع المعادلات !

المفروض بعد حل جميع المعادلات بالترتيب وتعريف جميع المتغيرات .. تعطينه أمر الطباعة print

[سملّق :)]

diva

وبخصوص برنامجك الثاني ،، هذا هو الكود

والاخطاء ( بالاحمر )

package paint;

import java.util.Scanner;
public class Paint {

    
    public static void main(String[] args) {

        
final int COVERAGE = 350 ;
final double SQUARE_FEET_PER_ONE_SQURAE_METER=10.764;
final int SQUARE_FEET_OF_DOOR= 20 ;
final int SQUARE_FEET_OF_WINDOW= 15;


int length , width , height , numDoor , numWindow ;
double totalSqFt;
double paintNeeded;
 

Scanner keyboard= new Scanner(System.in);
 

System.out.println("Enter length in meter");
length= keyboard.nextInt();
 

System.out.println("Enter width in meter");
width= keyboard.nextInt();
 

System.out.println("Enter height in meter");
  height= keyboard.nextInt();
 

  System.out.println("How many Doors in room? ");
  numDoor= keyboard.nextInt();
  
  System.out.println("How many Windows in room? ");
  numWindow= keyboard.nextInt();
 
  
  totalSqFt=(((length + width)*2*height)/10.764)-(numDoor+numWindow);
  System.out.println("The room  size is equal " +totalSqFt );
  
 
  paintNeeded= (totalSqFt / 350 ) ;
  System.out.println("The number of gallon of of paint needed is" + paintNeeded );
  

    }
}

الأخطاء :

كان المفروض انك قبل ما تسوين أمر " طباعة " تعرفين الـ total SqFt و الـ paint needed



1 = (أول شيء تعرفين المعادلة عشان يحلها الكمبيوتر أول شيء )
2 = وبعدين تحطين الناتج كمتغير في الأمر print !

عشان يكون البرنامج واضح لك وللكمبيوتر

[somyah]

السلام عليكم
اتمنى تساعدوني في حل هدا التمرين

Many private water wells produce only 1 or 2 gallons of water per minute. One way to avoid running out of water with these low-yield wells is to use a holding tank. A family of 4 will use about 250 gallons of water per day. However, there is a “natural” water holding tank in the casing (i.e. the hole) of the well itself. The deeper the well, the more water that will be stored that can be pumped out for household use. But how much water will be available?

Write a program that allows the user to input the radius of the well casing in inches (a typical well will have a 3 inch radius) and the depth of the well in feet (assume water will fill this entire depth, although in practice that will not be true since the static water level will generally be 50 feet or more below the ground surface). The program should output the number of gallons stored in the well casing. For your reference:

The volume of a cylinder is πr^2 h where r is the radius and h is the height.
1 cubic foot = 7.48 gallons of water.

For example, a 300 foot well full of water with a radius of 3 inches for the casing holds about 441 gallons of water -- plenty for a family of 4 and no need to install a separate holding tank.

Notes:

This project gives the student practice with numerical calculations and simple input/output. Introduces problem solving with relatively straightforward conversion of units. Students are likely to encounter data type conversion issues from double to int and vice versa (e.g. radius / 12 will result in 0 if radius is an int).



وجزاكم الله خير

[MNO0OL}~]

بليززز احد يساعدني في حل المشكلة هاذي

The Harris-Benedict equation estimates the number of calories your body needs to maintain your weight if you do no exercise. This is called your basal bolic rate or BMR.

The calories needed for a woman to maintain her weight is:
BMR = 655 + (4.3 * weight in pounds) + (4.7 * height in inches) - (4.7 * age in years)

The calories needed for a man to maintain his weight is:
BMR = 66 + (6.3 * weight in pounds) + (12.9 * height in inches) - (6.8 * age in years)

A typical chocolate bar will contain around 230 calories. Write a program that allows the user to input their weight in pounds, height in inches, and age in years. The program should then output the number of chocolate bars that should be consumed to maintain one’s weight for both a woman and a man of the input weight, height, and age.

Notes:

This project gives the student practice with numerical calculations and simple input/output. For a slightly more challenging problem allow the height to be entered in feet and inches and have the program convert to inches.

1 kg = 2.2046226218487757 pounds
1 m = 39.37007874015748 inches

[~Diva~]

مشكوووووووور ياسملق

[س.الرماح]

خطأين
التحويل بالضرب من كبير لصغير
المعادلة لابد تحتوي على مساحة النوافذ والابواب مضروبة بعددها

[MNO0OL}~]

ممكن احد يفهمني العملية اللي لازم اسويها عشان احول الوحدات
انا اسوي البرنامج (:


Many private water wells produce only 1 or 2 gallons of water per minute. One way to avoid running out of water with these low-yield wells is to use a holding tank. A family of 4 will use about 250 gallons of water per day. However, there is a “natural” water holding tank in the casing (i.e. the hole) of the well itself. The deeper the well, the more water that will be stored that can be pumped out for household use. But how much water will be available?

Write a program that allows the user to input the radius of the well casing in inches (a typical well will have a 3 inch radius) and the depth of the well in feet (assume water will fill this entire depth, although in practice that will not be true since the static water level will generally be 50 feet or more below the ground surface). The program should output the number of gallons stored in the well casing. For your reference:

The volume of a cylinder is πr^2 h where r is the radius and h is the height.
1 cubic foot = 7.48 gallons of water.

For example, a 300 foot well full of water with a radius of 3 inches for the casing holds about 441 gallons of water -- plenty for a family of 4 and no need to install a separate holding tank.

Notes:

This project gives the student practice with numerical calculations and simple input/output. Introduces problem solving with relatively straightforward conversion of units. Students are likely to encounter data type conversion issues from double to int and vice versa (e.g. radius / 12 will result in 0 if radius is an int).

[MNO0OL}~]

ليش هاذي غلط ؟؟؟؟؟؟؟؟؟؟؟

[عاشق الحاسب]

اخت منول
عندك خطاين في نفس السطر
١- لازم يكون عندك متغير تحطي في ناتج العملية وليكن double volume .
٢- في لغة الجافا طريقة الاس تختلف عن الرياضيات لان تستخدمي مكتبات مجهزة في اللغة فالصح في عملية الاس ٢ هي كالتالي : Math.pow(2.0,2.0)
double volume = 3.14*Math.pow(2.0,2.0)*d;
بالتوفيق