سؤال كيمياء

[R.O]

السلام عليكم

عندي سؤال ف الكيمياء

4. 25.0 mL of a 0.2450 M NH4Cl solution is added to 55.5 mL of 0.1655 M FeCl3. What is the concentration of chloride ion in the final solution?******A. 0.607 M
B. 0.418 M *
C. 1.35 M
D. 0.190 M
E. 0.276 M
مو المفروض الجواب يكون D ولا انا غلطانه

[ayar]

حطي المسألة كويس =\

[سعدوشه]

ناقص المعطى حق mL الاولى

[* تركي *]

moles = Molarity * liter = 0.2450 * 0.025 = 0.006125 moles of chloride ion in NH4Cl

moles = Molarity * liter = 0.1655 * 0.0555 = 0.00918525 moles of FeCl3

moles of chloride ion in FeCl3 = 0.00918525 * 3 = 0.02755

Total moles of chloride ion in the solution = 0.02755 + 0.006125 = 0.0336

Total volume = 0.0555 + 0.025 = 0.0805 L

Molarity = Moles / liters = 0.0336/0.0805 = 0.418 M